There are two containers of equal capacity. The ratio of milk to water in the first container is 3 : 1, in the second container 5 : 2. If they are mixed up, the ratio of milk to water in the mixture will be
There are two containers of equal capacity. The ratio of milk to water in the first container is 3 : 1, in the second container 5 : 2. If they are mixed up, the ratio of milk to water in the mixture will be
1). 28 : 41
2). 41 : 28
3). 15 : 41
4). 41 : 15
1 answers
Let the volume of the two containers be V.
Now,
? Milk to water ratio in the first container = 3 ? 1
⇒ Volume covered by milk = 3V/4 and Volume covered by water = V/4
In the second container, milk to water ratio = 5 ? 2
⇒ Amount of milk = 5V/7 and amount of water = 2V/7
When both the container’s content are mixed, amount of milk = $(\frac{{3V}}{4} + \frac{{5V}}{7} = \frac{{21V + 20V}}{{28}} = \frac{{41V}}{{28}})$
And amount of water = $(\frac{V}{4} + \frac{{2V}}{7} = \frac{{7V + 8V}}{{28}} = \frac{{15V}}{{28}})$
Now, Ratio of milk to water in the new mixture = $(\frac{{\frac{{41V}}{{28}}}}{{\frac{{15V}}{{28}}}} = \frac{{41}}{{15}} = 41\;:15)$