A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it ?
A). 20 days
B). 30 days
C). 40 days
D). 50 days
30 days
That is , A = 3B/2/1/2 = 3B/2
Replacing A by 3B/2, we get
3B/2× B/3B/2 + B = 18 days
3 B ×B/5B =18
3B = 90
B = 30 days, B alone can finish the work in 30 days.