If $sin\alpha + cos\alpha$ = 2 , $(0^{0} \leq \beta < \alpha \leq 90^{0})$,then $sin\left(\frac{2\alpha+\beta}{3}\right)$ =

If $sin\alpha + cos\alpha$ = 2 , $(0^{0} \leq \beta < \alpha \leq 90^{0})$,then $sin\left(\frac{2\alpha+\beta}{3}\right)$ =
1). $sin\frac{\alpha}{2}$
2). $cos\frac{\alpha}{3}$
3). $sin\frac{\alpha}{3}$
4). $cos\frac{2\alpha}{3}$

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