A can do a work in 9 days, if B is 50 % more efficient than A, then in how many days can B do the same work ?
1). 13.5 days
2). 4.5 days
3). 6 days
4). 3 days
Let total work to be done=1
Then, A's one day work= (total work) / (total days taken by A)
(=1/9)B's one day work= 150% of A's one day work (because B is 50% more efficient)
=(1/9)*(150/100)
=1/6 Total time taken by B to do total work = 6 days