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31 vote

A can do a work in 9 days, if B is 50 % more efficient than A, then in how many days can B do the same work ?

Asked on by | Votes 31 | Views: 1283 | Tags: time and work     | quantitative aptitude     | ssc chsl 2011     | Add Bounty

A can do a work in 9 days, if B is 50 % more efficient than A, then in how many days can B do the same work ?
1). 13.5 days
2). 4.5 days
3). 6 days
4). 3 days


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2 answers

29 vote
Answered by on | Votes 29 |
Hello, 6 days is correct

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26 vote
Answered by on | Votes 26 |

Let total work to be done=1

Then, A's one day work= (total work) / (total days taken by A)

(=1/9)B's one day work= 150% of A's one day work (because B is 50% more efficient)

=(1/9)*(150/100)

=1/6 Total time taken by B to do total work = 6 days

Accepted Answer




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