Let $\sqrt[3]{a}$ = $\sqrt[3]{26}+\sqrt[3]{7}+\sqrt[3]{63}$ , then

Let $\sqrt[3]{a}$ = $\sqrt[3]{26}+\sqrt[3]{7}+\sqrt[3]{63}$ , then
1). a < 729 but a > 216
2). a < 216
3). a > 729
4). a = 729

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