If $27^{2x-1}=(243)^{3}$ , then the value of x is
1). 3
2). 6
3). 7
4). 9
1. $9\sqrt{x}$=$\sqrt{12}+\sqrt{147}$ , then x=
3. Solve for x: $3^{x}-3^{x-1}$ = 486.
5. If $3^{2x-y}$=$3^{x+y}$=$\sqrt{27}$. then the value of $3^{x-y}$ will be
6. If $\sqrt{7}$ = 2.646, then the value of $\frac{1}{\sqrt{28}}$ upto three places of decimal is :-