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The number, which when multiplies with $(\sqrt{3}+\sqrt{2})$ gives $(\sqrt{12}+\sqrt{18})$ is :

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The number, which when multiplies with $(\sqrt{3}+\sqrt{2})$ gives $(\sqrt{12}+\sqrt{18})$ is :
1). $3\sqrt{2}-2\sqrt{3}$
2). $3\sqrt{2}+2\sqrt{3}$
3). $\sqrt{6}$
4). $2\sqrt{3}-3\sqrt{2}$

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Answered by on | Votes 1 |
Correct answer is: option 3

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