If x = $\frac{1}{\sqrt{2}+1}$ , then (x+1) is equal to

If x = $\frac{1}{\sqrt{2}+1}$ , then (x+1) is equal to
1). 2
2). $\sqrt{2}$
3). $\sqrt{2}+1$
4). $\sqrt{2}-1$

SSC CGL Books

---

Join Telegram Group

Answer This Question
Name:
Email:
Answer :
Sum of (3+3)
Submit:

Other Questions

1. $\left\{(-2)^{(-2)}\right\}^{(-2)}$ is equal to :

2. The total number of prime factors in $4^{10}+7^{3}+16^{2}+11+10^{2}$ is :-

3. What to the product of the roots of the equation $x^{2}-\sqrt{3}$=0

4. Given that $\sqrt{3}$ =1.732, then the value of $\frac{3 + \sqrt{6}}{5\sqrt{3}-2\sqrt{12}-\sqrt{32}+\sqrt{50}}$ is :

5. $16^{\frac{3}{4}}$ is equal to :

6. $\sqrt{12+\sqrt{12+\sqrt{12+.....}}}$ is equal to

7. $\frac{0.3555\times 0.5555\times 2.025}{0.225\times 1.7775\times 02222}$ is equal to :

8. The value of $\sqrt{11+2\sqrt{30}}-\frac{1}{\sqrt{11+2\sqrt{30}}}$ is :

9. The simplified value of $(\sqrt{3}+1) (10 +\sqrt{12} ) (\sqrt{12} -2) (5-\sqrt{3})$ is :

10. $2\sqrt[3]{40}-4\sqrt[3]{320}+3\sqrt[3]{625}-3\sqrt[3]{5}$ is equal to :