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22 vote

The largest number, which divides 25, 73 and 97 to leave the same remainder In each case, is

Asked on by | Votes 22 | Views: 1310 | Tags: mathematics     | hcf and lcm     | quantitative aptitude     | ssc     | Add Bounty

The largest number, which divides 25, 73 and 97 to leave the same remainder In each case, is
1). 24
2). 23
3). 21
4). 6

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2 answers

3 vote
Answered by on | Votes 3 |
option 1 is the answer

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53 vote
Answered by on | Votes 53 |

Let x be the remainder. Then, $(25 – x ), (73 – x ),$ and $(97 – x )$ Will be exactly divisible by the required number.

Required number = HCF of $(73 –x ) – (25 –x ), (97 –x ) – (73 –x )$ and $(97 –x ) – (25 –x ) =$ HCF of $(73 –25), (97 –73),$ and $(97 –25)$

$= $HCF of $48, 24$ and $72 = 24$




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