The sum of a pair of positive integer is 336 and their H.C.F. is 21. The number of such possible pairs is
1). 2
2). 3
3). 4
4). 5
Let the numbers be 21x and 21y where x and y are prime to each other.
21x + 21y = 336
21 (x + y) = 336
x + y =$\frac{336}{21}$ = 16
Possible pairs = (1, 15), (5, 11), (7, 9), (3, 13)
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