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Find the greatest number of five digits which when divided by 3. 5. 8. 12 have 2 as remainder :
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Find the greatest number of five digits which when divided by 3. 5. 8. 12 have 2 as remainder :
1). 99999
2). 99958
3). 99960
4). 99962
2 answers
2 vote
is option 4 is the correct answer am i right
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Using Rule 4,
The greatest number of five digits
is 99999.
LCM of 3, 5, 8 and 12
LCM = 2 × 2 × 3 × 5 × 2 = 120
After dividing 99999 by 120, we
get 39 as remainder
99999 – 39 = 99960
= (833 × 120)
99960 is the greatest five digit
number divisible by the given divisors.
In order to get 2 as remainder in
each case we will simply add 2
to 99960.
Greatest number
= 99960 + 2 = 99962
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