Sum of two numbers is 384. H.C.F. of the numbers is 48. The difference of the numbers is
1). 100
2). 192
3). 288
4). 336
Let the numbers be 48x and 48y where x and y are co-primes.
48x + 48y = 384 Þ 48 ( x + y) = 384 Þ x + y = 384 / 48 = 8 ........... (i)
Possible and acceptable pairs of x and y satisfying this condition are : (1, 7) and (3, 5).
Numbers are : 48 × 1 = 48 and 48 × 7 = 336 and 48 × 3 = 144 and 48 × 5 = 240
Required difference = 336 – 48 = 288
2. The HCF of two numbers is 15 and their LCM is 300. If one of the number is 60, the other is :
5. The greatest number that divides 411, 684, 821 and leaves 3, 4 and 5 as remainders, respectively, is
10. The greatest number, that divides 122 and 243 leaving respectively 2 and 3 as remainders, is