The greatest number, that divides 122 and 243 leaving respectively 2 and 3 as remainders, is
1). 12
2). 24
3). 30
4). 120
Clearly, $122 – 2 = 120$ and $243 – 3 = 240$ are exactly divisible by the required number.
Required number $=$ HCF of $120, 240 = 120$
4. Find the greatest number of five digits which when divided by 3. 5. 8. 12 have 2 as remainder :
5. The ratio of two numbers is 4:5 and their H.C.F. is 8. Then their L.C.M. is
9. The least perfect square, which is divisible by each of 21. 36 and 66 1s
10. Two numbers are in the ratio 3:4. If their HCF is 4, then their LCM is