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52 vote

If the HCF and LCM of two consecutive (positive) even numbers be 2 and 84 respectively, then the sum of the numbers is

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If the HCF and LCM of two consecutive (positive) even numbers be 2 and 84 respectively, then the sum of the numbers is
1). 30
2). 26
3). 14
4). 34

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3 answers

22 vote
Answered by on | Votes 22 |
Its very simple question 26 is the correct answer.

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15 vote
Answered by on | Votes 15 |
we know that HCF×LCM=ist No.×2nd No. let the one no.be x then the consecutive even no.=x+2 so,$x(x+2)=2×84=168$ $x^2 +2x-168=0$ splitting middle term we get $x^2+14x-12x-168=0$ $x(x+14)-12(x-14)=0$ $x+14=0 or x-12=0$ we take $x-12=0$ becoz $x+14$ will give -ve value of x so $x=12 $ & $x+2=14$ .'. $x+(x+2)=26$ so the sum of two consecutive even no.s with hcf $=2$ and lcm $=84$ is $26$.
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30 vote
Answered by on | Votes 30 |
Let the numbers be 2x and 2y where x and y are prime to each other. LCM = 2xy 2xy = 84 xy = 42 = 6 × 7 Numbers are 12 and 14. Hence Sum = 12 + 14 = 26