A number x is divisible by 7. When this number is divided by 8, 12 and 16. It leaves a remainder 3 in each case. The least value of x is:
A number x is divisible by 7. When this number is divided by 8, 12 and 16. It leaves a remainder 3 in each case. The least value of x is: 1). 148 2). 149 3). 150 4). 147
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2 answers
Answered by
Guest on
2018-01-20 03:47:41 | Votes
34 |
#
I have read it somewhere 147 is correct
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Answered by
Guest on
2018-04-10 22:41:55 | Votes
0 |
#
LCM of 8, 12 and 16 = 48
Required number
= 48a + 3 which is divisible by 7.
x = 48a + 3
= (7 × 6a) + (6a + 3) which is
divisible by 7.
i.e. 6a + 3 is divisible by 7.
When a = 3, 6a + 3 = 18 + 3
= 21 which is divisible by 7.
x = 48 × 3 + 3 = 144 + 3 = 147
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