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22 vote

A number x is divisible by 7. When this number is divided by 8, 12 and 16. It leaves a remainder 3 in each case. The least value of x is:

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A number x is divisible by 7. When this number is divided by 8, 12 and 16. It leaves a remainder 3 in each case. The least value of x is:
1). 148
2). 149
3). 150
4). 147

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2 answers

34 vote
Answered by on | Votes 34 |
I have read it somewhere 147 is correct

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0 vote
Answered by on | Votes 0 |
LCM of 8, 12 and 16 = 48 Required number = 48a + 3 which is divisible by 7. x = 48a + 3 = (7 × 6a) + (6a + 3) which is divisible by 7. i.e. 6a + 3 is divisible by 7. When a = 3, 6a + 3 = 18 + 3 = 21 which is divisible by 7. x = 48 × 3 + 3 = 144 + 3 = 147




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