Algebra Question and Answers 14 ExamCompetition

Algebra Practice Questions & Answers

0 vote

Asked on 2019-07-07 21:46:27 by | Votes 0

In the following question two equations I and II are given. You have to solve these equations and determine relation between the variables given.

I. 3x² – 13x + 14 = 0

II. 3y² + 11y + 10 = 0
1). x < y
2). x > y
3). x = y or the relationship cannot be determined
4). x ≥ y

37 vote

Asked on 2019-07-07 17:45:53 by | Votes 37

x³ + y³ = 35 and x + y = 5, then the value of (1/x + 1/y) is
1). 4/7
2). 3/8
3). 5/6
4). 3/5

0 vote

Asked on 2019-07-07 16:42:27 by | Votes 0

In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer

I. a²– 32a = 0

II. b² + 121b = 0
1). a < b
2). a > b
3). a ≤ b
4). a ≥ b

0 vote

Asked on 2019-07-07 15:53:55 by | Votes 0

The value of \(\frac{{{{\left( {0.04} \right)}^2} - {{\left( {0.01} \right)}^2}}}{{0.04 - 0.01}}\) is
1). 0.06
2). 0.005
3). 0.5
4). 0.05

0 vote

Asked on 2019-07-07 14:37:33 by | Votes 0

Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer:

I. \(\frac{{17}}{{\sqrt x }}\) = √x – \(\frac{7}{{\sqrt x }}\)

II. y³ – \(\frac{{\left( {3\;\times \;8} \right)\frac{9}{2}}}{{y\sqrt y }}\) = 0
1). if x > y
2). if x ≥ y
3). if x < y
4). if x ≤ y