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Miscellenaeous Practice Questions & Answers

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Following questions are completely based upon numbers. In the test, every question consists of four numbers labeled as option A, B, C and D. Your task is to find out the group of digits which contains a “9”. If digit “9” exists in any number (option) then your answer is that option. If more than one number (option) has digit 9, the answer will be E. A.2822032   B.1475015   C.2578081   D.3933061

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Following questions are completely based upon numbers. In the test, every question consists of four numbers labeled as option A, B, C and D. Your task is to find out the group of digits which contains a “9”. If digit “9” exists in any number (option) then your answer is that option. If more than one number (option) has digit 9, the answer will be E
A.2822032   B.1475015   C.2578081   D.3933061
1). A
2). B
3). C
4). D

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If the sum of two numbers is 35 and the LCM and HCF of the same numbers are 60 and 5 respectively. The value of larger number is:

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If the sum of two numbers is 35 and the LCM and HCF of the same numbers are 60 and 5 respectively. The value of larger number is:
1). 25
2). 10
3). 12
4). 20

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In the following questions, some numbers are given at the left side and some are at the right side too. If numbers of both sides are same, then answer would be ‘Y’ (Yes) and if numbers are different the answer will be ‘N’ (No).A. 190528   B. 190628

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In the following questions, some numbers are given at the left side and some are at the right side too. If numbers of both sides are same, then answer would be ‘Y’ (Yes) and if numbers are different the answer will be ‘N’ (No).
A. 190528   B. 190628
1). Y
2). N
3).
4).

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If tan A = 1 and tan \(B = \sqrt 3 \) then value of cos (A + B) is

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If tan A = 1 and tan \(B = \sqrt 3 \) then value of cos (A + B) is
1). \(\frac{{1 + \sqrt 3 }}{{2\sqrt 2 }}\)
2). \(\frac{{1 - \sqrt 3 }}{{\sqrt 2 }}\)
3). \(\frac{{1 - \sqrt 3 }}{{2\sqrt 2 }}\)
4). \(\frac{{1 + \sqrt 3 }}{4}\)

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Find the sum of the given terms. \(\frac{1}{{\left( {{2^2} - 1} \right)}} + \frac{1}{{\left( {{4^2} - 1} \right)}} + \frac{1}{{({6^2} - 1)}} + ... + \frac{1}{{({{20}^2} - 1)}}\)

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Find the sum of the given terms.

\(\frac{1}{{\left( {{2^2} - 1} \right)}} + \frac{1}{{\left( {{4^2} - 1} \right)}} + \frac{1}{{({6^2} - 1)}} + ... + \frac{1}{{({{20}^2} - 1)}}\)


1). 9/10
2). 10/11
3). 19/21
4). 10/21