4 men and 3 women finish a job in 6 days, and 5 men and 7 women can do the same job in 4 days. How long will 1 man and 1 woman take to do the work ?
1). 22 2/7 days
2). 25 1/2 days
3). 5 1/7 days
4). 12 7/22 days
Let the time taken to complete the work = $x$ days
=> $(4 M + 3 W) \times 6 = (5 M + 7 W) \times 4$
=> $24 M + 18 W = 20 M + 28 W$
=> $4 M = 10 W$ ---------------Eqn(1)
Acc to ques,
=> $(4 M + 3 W) \times 6 = (1 M + 1 W) \times x$
Using eqn(1), we get :
=> $(10 + 3) \times 6 = (\frac{10}{4} + 1) \times x$
=> $78 = \frac{7}{2} x$
=> $x = \frac{78 \times 2}{7} = \frac{156}{7}$
=> $x = 22\frac{2}{7}$ days
Let the time taken to complete the work = $x$ days
=> $(4 M + 3 W) \times 6 = (5 M + 7 W) \times 4$
=> $24 M + 18 W = 20 M + 28 W$
=> $4 M = 10 W$ ---------------Eqn(1)
Acc to ques,
=> $(4 M + 3 W) \times 6 = (1 M + 1 W) \times x$
Using eqn(1), we get :
=> $(10 + 3) \times 6 = (\frac{10}{4} + 1) \times x$
=> $78 = \frac{7}{2} x$
=> $x = \frac{78 \times 2}{7} = \frac{156}{7}$
=> $x = 22\frac{2}{7}$ days