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Directions : In the following questions, the symbols ?, #, @, ? and $ are used with the following meaning as illustrated below: P ? Q means P is not greater than Q. P # Q means P is neither greater than nor equal to Q P @ Q means P is neither greater than nor smaller then Q P ? Q means P is neit

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Directions : In the following questions, the symbols ?, #, @, ? and $ are used with the following meaning as illustrated below:
P ? Q means P is not greater than Q.
P # Q means P is neither greater than nor equal to Q
P @ Q means P is neither greater than nor smaller then Q
P ? Q means P is neither smaller than or equal to Q
P $ Q means P is not smaller than Q.
Now in each of the following questions assuming the given statements to be true, find which of the conclusions given below them are definitely true?


Statements U @ N, N $ F, F $ A, A ? R
Conclusions
I. A @ U
II. N ? R
III. R ? U
IV. U ? A
1). Only II is true
2). Only I and II are true
3). Only I, II and IV are true
4). Only III and IV are true

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2 answers

2 vote
Answered by on | Votes 2 |
Solution

U@N means U is neither greater nor smaller than N
means,U=N
N$F means N is not smaller than F
means N>=F
Similarly F$A means F>=A
A€R means A is neither smaller nor equal to R
means A>R
Combining all the inference we get,
U=N
N>=F>=A>R
Conclusion 2 is N€R means N>=R which is definitely true according to the inference drawn from the given statements
Conclusion 1 is A@U means A=U which might be possible because U=N and N>=A otherwise U>A which is stated in 4th conclusion.
Hence option E

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1 vote
Answered by on | Votes 1 |
Solution

U@N means U is neither greater nor smaller than N
means,U=N
N$F means N is not smaller than F
means N>=F
Similarly F$A means F>=A
A€R means A is neither smaller nor equal to R
means A>R
Combining all the inference we get,
U=N
N>=F>=A>R
Conclusion 2 is N€R means N>=R which is definitely true according to the inference drawn from the given statements
Conclusion 1 is A@U means A=U which might be possible because U=N and N>=A otherwise U>A which is stated in 4th conclusion.
Hence option E




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