Anuj’s age is 1/6th of Biju’s age. Biju’s age will be twice of Cessi’s age after 10 years. If Cessi’s 8th birthday was celebrated two years ago, then determine the present age of Anuj.
1). 20 years
2). 15 years
3). 5 years
4). 10 years
Let Anuj’s age be ‘x’ and that of Biju be ‘y’,
⇒ x = y/6
Let Cessi’s age be ‘z’.
After 10 years, y + 10 = 2(z + 10) ⇒ y + 10 = 2z + 20 ⇒ y = 2z + 10
Now, Cessi’s 8th birthday was celebrated 2 years ago = z = 8 + 2 = 10 years.
⇒ y = 2 × 10 + 10 = 30 years.
∴ Anuj’s age = x = y/6 = 30/6 = 5 years.Let Anuj’s age be ‘x’ and that of Biju be ‘y’,
⇒ x = y/6
Let Cessi’s age be ‘z’.
After 10 years, y + 10 = 2(z + 10) ⇒ y + 10 = 2z + 20 ⇒ y = 2z + 10
Now, Cessi’s 8th birthday was celebrated 2 years ago = z = 8 + 2 = 10 years.
⇒ y = 2 × 10 + 10 = 30 years.
∴ Anuj’s age = x = y/6 = 30/6 = 5 years.2. If $sec^{2}\theta+tan^{2}\theta=\sqrt{3},$ then the value of $sec^{2}\theta-tan^{2}\theta$ is
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