A can do a piece of work in 20 days. He worked for 4 days and B finished the remaining work in 28 days. B alone can do the whole work in how many days?
1). 28
2). 32
3). 35
4). 42
Let, B can do the work in = x days
∴ 1 day’s work of B = 1/x
A can do a piece of work in = 20 days
∴ 1 day’s work of A = 1/20
According to problem,
$( \Rightarrow \frac{4}{{20}} + \frac{{28}}{x} = 1)$
$( \Rightarrow \frac{{4x + 560}}{{20x}} = 1)$
⇒ 20x = 4x + 560
⇒ 16x = 560
⇒ x = 35
∴ B alone can do the whole work in = 35 days