Three pipes A, B and C can fill a cistern in 36 minutes. After working together for 12 minutes, C is closed and A and B fill the cistern in 48 minutes. Find the time in which the cistern can be filled
A). 61 min
B). 67 min
C). 72 min
D). 76 min
72 min
The part of the tank (A + B + C), working together, will fill in 12 min = 12/36 = 1/3
Hence remaining tank = (1 - 1/3) = 2/3 is filled by (A + B) in 48 min
∴ A + B till the tank in 48x3/2 = 72 min
The part of the C can fill in 1 minute= 1/(A+B+C) - 1/(A+B) = 1/36 - 1/72 = 1/72
So, C can fill the whole tank in 72 minutes.