Simplify ; $\left[\sqrt[3]{\sqrt[6]{5^{9}}}\right]^{4}$
1). $5^{2}$
2). $5^{4}$
3). $5^{8}$
4). $5^{12}$
1. Arranging the following in ascending order $3^{34}$,$2^{51}$,$7^{17}$ , we get
2. $\frac{3\sqrt{2}+2\sqrt{3}}{3\sqrt{2}-2\sqrt{3}}$ is equal to
3. Simplify ; $\left[\sqrt[3]{\sqrt[6]{5^{9}}}\right]^{4}$
4. $\frac{\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}}{\sqrt[3]{8}}$ =
5. The unit digit in the product $(2467)^{155}\times (341)^{72}$ is
6. $\frac{12}{3+\sqrt{5}+2\sqrt{2}}$ is equal to
7. $2\sqrt[3]{40}-4\sqrt[3]{320}+3\sqrt[3]{625}-3\sqrt[3]{5}$ is equal to :
9. By how much does $\sqrt{12}+2\sqrt{18}$ exceed $2\sqrt{3}+2\sqrt{2}$