Two numbers, both greater than 29, have HCF 29 and LCM 4147. The sum of the numbers is : 1). 966 2). 696 3). 669 4). 666
Let the number be 29x and 29y respectively where x and y are prime to each other.
LCM of 29x and 29y = 29xy
Now, 29xy = 4147 xy =$\frac{4147}{29}$ = 143
Thus xy = 11 × 13
Numbers are 29 × 11 = 319 and 29 × 13 = 377
Required sum = 377 + 319 = 696
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