If the product of two successive positive integers is 3192, which is the smaller integer?
If the product of two successive positive integers is 3192, which is the smaller integer?
1). 52
2). 58
3). 54
4). 56
2 answers
Let the two successive positive integers be $(x)$ & $(x + 1)$
Acc to ques,
=> $(x) \times (x + 1) = 3192$
=> $x^2 + x - 3192 = 0$
=> $x = \frac{-1 \pm \sqrt{(1^2) - (4 \times 1 \times -3192)}}{2}$
=> $x = \frac{-1 \pm \sqrt{21769}}{2}$
=> $x = \frac{-1 \pm 113}{2}$
=> $x = 56 , -57$
Since the numbers are positive, => $x = 56$
$\therefore$ Smaller number = 56
Let the two successive positive integers be $(x)$ & $(x + 1)$
Acc to ques,
=> $(x) \times (x + 1) = 3192$
=> $x^2 + x - 3192 = 0$
=> $x = \frac{-1 \pm \sqrt{(1^2) - (4 \times 1 \times -3192)}}{2}$
=> $x = \frac{-1 \pm \sqrt{21769}}{2}$
=> $x = \frac{-1 \pm 113}{2}$
=> $x = 56 , -57$
Since the numbers are positive, => $x = 56$
$\therefore$ Smaller number = 56