A and B can do a piece of work in 10 days. B and C can do it in 12 days; C and A in 15 days. In how many days will C finish it alone?
1). 24 days
2). 30 days
3). 40 days
4). 60 days
Given,
⇒ A + B = 1/10
⇒ B + C = 1/12
⇒ A + C = 1/15
Adding above equations,
⇒ 2(A + B + C) = (1/10) + (1/12) + (1/15)
⇒ A + B + C = 1/8
C's 1 day’s work =
= (A + B + C)’s 1 day’s work – (A + B)’s 1 day’s work
= 1/8 – 1/10
= 1/40
∴ C alone can complete the work in 40 days.