In each of the following questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.
Give answer If
a: x > y
b: x ? y
c: x ? y
d: x < y
e: Relationship between x and y cannot be established
I.$x^{2} - x - 12 = 0$
=> $x^2 - 4x + 3x - 12 = 0$
=> $x (x - 4) + 3 (x - 4) = 0$
=> $(x - 4) (x + 3) = 0$
=> $x = 4 , -3$
II.$y^{2} + 4y + 4 = 0$
=> $y^2 + 2y + 2y + 4 = 0$
=> $y (y + 2) + 2 (y + 2) = 0$
=> $(y + 2) (y + 2) = 0$
=> $y = -2 , -2$
Because $4 > -2$ and $-2 > -3$
$\therefore$ No relation can be established.